Question

Nomor 1 dan 2 tolong dijawab ya........

Answer 1

Jawab Nomor 1

Gaya lekat paku (Fp) 
F x s = Fp x h 
9.4 x 10⁴ x 1.5 = Fp x 0.25 
Fp = 14.1x10⁴ / 0.25 
= 56.4 x 10⁴ N
KM = 1,5/0,25 = 6

Jawab Nomor 2

a. Katrol tetap 
F = W 
KM = 1 
b. Katrol bergerak 
F = W/2 
KM = W / F = 2 
c. Takal 4 katrol >> n = 4 
KM = n = 4