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p = cos x maka persamaan tersebut menjadi 12p² - p - 1 = 0 diperoleh
p1 + p2 = 1/12
p1p2 = -1/12
Ingat bahwa sec x = 1/cos = 1/p maka
sec² x1 + sec² x2
= 1/p1² + 1/p2²
= (1/p1 + 1/p2)² - 2(1/p1 . 1/p2)
= ((p1+p2)/p1p2)² - 2(1/p1p2)
= (-1)² - 2(-12)
= 1 + 24
= 25
jawaban: B