Question

Nomer 2 caranya gimana ya?

Answer 1

Cos B = AB/BD
cos 45°= 10/BD
√2/2 = 10/BD
BD = 20/√2

cos D = CD/BD
cos 60° = CD /(20/√2)
1/2 = √2CD/20
CD=20/2√2
= 10/√2
=5√2

Answer 2

Cos 45° = 10/BD
1/2√2 = 10/BD
    BD = 10√2 

cos 60° = CD/BD
       1/2 = CD/10√2
       CD = (10√2)/2
       CD = 5√2