Respuesta:
N=
[tex]x \leqslant = 3 \\ 3.2.1[/tex]
[tex]2(3) - 1 = 6 - 1 = 5 \\ 2(2) - 1 = 4 - 1 = 3 \\ 2(1) - 1 = 2 - 1 = 1 \\ \\ 5 + 3 + 1 = 9[/tex]
alternativa B
Explicación paso a paso:
espero te ayude
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Respuesta:
N=
[tex]x \leqslant = 3 \\ 3.2.1[/tex]
[tex]2(3) - 1 = 6 - 1 = 5 \\ 2(2) - 1 = 4 - 1 = 3 \\ 2(1) - 1 = 2 - 1 = 1 \\ \\ 5 + 3 + 1 = 9[/tex]
alternativa B
Explicación paso a paso:
espero te ayude