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B = (1 1/2)(A) ⇒ B = (3/2)(A) ⇒ A = (2/3)B
Sehingga
C = 2A
⇒ C = 2(2/3)B
⇒ C = (4/3)B
Sehingga
A + B + C = 180
⇒ (2/3)B + B + (4/3)B = 180
⇒ 3B = 180
⇒ B = 60°
dan
A = (2/3)(B)
⇒ A = (2/3)(60)
⇒ A = 40°
C = (4/3)(B)
⇒ C = (4/3)(60)
⇒ C = 80°
Jadi
∠A = 40°, ∠B = 60°, ∠C = 80°
Terimakasih semoga membantu
10x + 70 = 180
10x = 180 - 70
10x = 110
x = 110/10
x = 11
8) ∠A = (1/2)C ∠B = 1 1/2C
∠A : ∠C = 1 : 2 ∠B = (3/2)C
∠B : ∠C = 3 : 2
Dari kedua persamaan diperoleh:
∠A : ∠C = 1 : 2 ∠A = 2 (dari perkalian silang 1 X2)
∠B : ∠C = 3 : 2 ∠B = 6 (dari perkalian silang 2 X3)
∠C = 4 (dari perkalian silang 2 X2)
___ +
12
Besar sudut Δ jika dijumlahkan = 180 derajat
Maka :
Besar ∠A = (2/12) . 180 = 30 derajat
Besar ∠A = (6/12) . 180 = 90 derajat
Besar ∠A = (4/12) . 180 = 60 derajat