Question

No 6 dan 8 aja kak tolong kak ini ulangan saya.​

Answer 1

Penjelasan dengan langkah-langkah:

VEKTOR

6. ê = i – 2j – 2k

ē = (1, –2, –2)

7. PQ : PS = 2 : 3

QP : PS = –2 : 3

–2QP = 3PS

–2(–8, 8, 8) = 3(x–3, y+1, z+2)

3x = 16+9 → x = 25/3

3y = –16–3 → y = –19/3

3z = –16–6 → z = –22/3

S = ⅓(25, –19, –22)

RS = ⅓(25–12, –19+9, –22–27)

RS = (13/3, –10/3, –49/3)

RS = 13i/3 – 10j/3 – 49k/3

8. sin ∅ = 3/5 → cos ∅ = 4/5

q(2p – q) = 2pq – q² + (2pq)(q²) cos ∅

q(2p – q) = 2×10×2 – 10² + (40)(100)4/5

q(2p – q) = 40 – 100 + 3.200

q(2p – q) = 3.140