Question

No 5 tolong bantuin yaa

Answer 1

Kurva melalui (-3, 0), (1, 0), dan (-1, 4)

f (x) = ax² + bx + c
f (-3) = 0

a(-3)² + b(-3) + c = 0
9a - 3b + c = 0

f (1) = 0
a(1)² + b(1) + c = 0
a + b + c = 0

9a - 3b + c = a + b + c
9a - a - 3b - b + c - c = 0
8a - 4b = 0


f (-1) = 4
a(-1)² + b(-1) + c = 4
a - b + c = 4

eliminasi

a + b + c = 0
a - b + c = 4 -
2b = -4
b = -4/2
b = -2

8a - 4b = 0
8a - 4(-2) = 0
8a + 8 = 0
8a = -8
a = -8/8
a = -1

a + b + c = 0
-1 - 2 +c = 0
-3 + c = 0
c = 3

f (x) = ax² + bx + c
f (x) = -x² - 2x + 3
y = -x² - 2x + 3
→ E.