iday
Pake konsep grafitasi Newton : g = F/m ---> g = G x (M/r^2) grvitasi itu berbanding terbalik kuadrat jaraknya No. 3 g" = (r/(r + h))^2 x g ---> g" = (R/(R + 1/3R))^2 x 9,8 ---> g" = 5,51 m/s^2 jawab : C
No. 4 gA : gB = (mA/mB) x (rB/rA)^2 ---> gA ; gB = (2m/m) x (R/2R)^2 gA : gB = 1 : 2 ---> jawab A
grvitasi itu berbanding terbalik kuadrat jaraknya
No. 3
g" = (r/(r + h))^2 x g ---> g" = (R/(R + 1/3R))^2 x 9,8 ---> g" = 5,51 m/s^2 jawab : C
No. 4
gA : gB = (mA/mB) x (rB/rA)^2 ---> gA ; gB = (2m/m) x (R/2R)^2
gA : gB = 1 : 2 ---> jawab A