Question

No 3,4,5 tlg bgt buat tryout biar lulus

Answer 1

3.
(ab)² X (-2ac)³
= a²b² X (-2)³a³c³
= a²b² X (-8)a³c³
= -8a^5 b² c³ (jawaban c.)

4.
∛9.261 - √196 + ∛625
= 21 - 14 + ∛(125*5)
= 7 + 5(∛5)

5.
= ∛(a^10 a²) per (a^2/3 a^1/3)
= ∛a^12 per (a)
= a^4 / a
= a³

Maaf, kalau salah..
Semoga membantu.. :) !!

Answer 2

3.
(ab)^2 x (-ac)^3
= -8.b^2.c^3.a^5

4.
3V9261 - 2V196 + 3V625
21 - 14 + 5(3V5)
7 + 5 (3V5)

5.
a^(10+2)/3 
-----------------------------------
a^2/3 . a^1/3

a^(12/3)
-----------------  atau 
a