No 3 please ,yg bisa respon.
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(2x-4)^2 = 4x
4x^2 - 16x + 16 - 4x = 0
4x^2 - 20 x + 16= 0
x^2 - 5x + 4 = 0
Uji dengan D= b^2 - 4ac
D= 25 -4(1)(4) = 9
D = 9 ----> D > 0
krn D > 0 saling memotong di dua titik
titk pot nya
x^2 - 5x + 4= 0
(x-4)(x-1) = 0
x = 4 maka y = 2x -4 = 4 --> (4,4)
x= 1 maka y = 2x -4 = - 2 --> (1, -2)