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S = (1/5 + 1/5^3 + 1/5^5 + ...) + (2/5^2 + 2/5^4 + 2/5^6 + ....)
S1 S2
S1 dan S2 merupakan deret geometri takhingga dengan
r = 1/25
Menentukkan S1
a = 1/5
S1 = a/(1 - r)
= (1/5) /(1 - 1/25)
= (1/5)/(24/25)
= 5/24
Menentukan S2
a = 2/25
S2 = (2/25)/(1 - 1/25)
= (2/25)/(24/25)
= 2/24
Jadi S = S1 + S2
= 5/24 + 2/24
= 7/24