misal:
a + b = 52
a = 2b + 7 ----substitusi ke pers di atasnya
2b + 7 + b = 52
3b = 52 - 7
3b = 45
b = 45/3
b = 15
Menentukan banyak siswa laki-laki
a + 15 = 52
a = 52 - 15
a = 37 siswa
Jawaban:
B
Penjelasan dengan langkah-langkah:
SPLDV
L + P = 52
P = 52 – L
L = 2P + 7
→ P = 52 – (2P + 7)
P = 52 – 2P – 7
P + 2P = 52 – 7
3P = 45
P = 45
3
P = 15
L = 2×15 + 7
L = 30 + 7
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misal:
a + b = 52
a = 2b + 7 ----substitusi ke pers di atasnya
a + b = 52
2b + 7 + b = 52
3b = 52 - 7
3b = 45
b = 45/3
b = 15
Menentukan banyak siswa laki-laki
a + b = 52
a + 15 = 52
a = 52 - 15
a = 37 siswa
Jawaban:
B
Penjelasan dengan langkah-langkah:
SPLDV
L + P = 52
P = 52 – L
L = 2P + 7
→ P = 52 – (2P + 7)
P = 52 – 2P – 7
P + 2P = 52 – 7
3P = 45
P = 45
3
P = 15
L = 2P + 7
L = 2×15 + 7
L = 30 + 7
L = 37