Question

No 12 saja + pembahasan

Answer 1

A. 2' log 3 . 3' log 5 = pq
2' log 5 = pq

b. 6' log 5
= 2' log 5 / 2' log 6
= pq / (2' log 2 2' log 3)
= pq / (1 + p)

c. 5' log 4,5
= 5' log (9/2)
= 5' log 9 - 5' log 2
= 5' log 3^2 - 5' log 2
= 2 (5' log 3) - 5' log 2
= 2 (1/(3' log 5)) - 1/(2'log5)
= 2/q - 1/pq
= 2p/pq - 1/pq
= (2p - 1) / pq