eksponen
no. 1
•
no. 2
(3 + 2√2)²
= 3² + 2(3)(2√2) + (2√2)²
= 9 + 12√2 + 8
= 17 + 12√2
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eksponen
no. 1
•
no. 2
(3 + 2√2)²
= 3² + 2(3)(2√2) + (2√2)²
= 9 + 12√2 + 8
= 17 + 12√2
•