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(x+1) adalah a
maka
(x+1)^2 - 5(x+1) + 6> 0
<=>a^2 - 5a + 6 > 0
<=> ( a - 3 ) ( a - 2 ) > 0
<=> a > 3 V a > 2
maka 2 < a < 3
jadi
x+1 < 3 V x+1 > 2
x1 < 2 V x2 > 1
semoga bermanfaat