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Dengan daerah:
Solusi:
1 < x < 2
3^2x - 4 . 3^x . 3 + 27 < 0
3^x2 - 12 . 3^x + 27 < 0
misalkan 3^x = p, maka
p^2 - 12p + 27 < 0
(p - 3) (p - 9) < 0
p = 3 atau p = 9
td kan kita misalkan 3^x = p
maka 3^x = 3 3^x = 9
x = 1 x = 2
1 < x < 2