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Verified answer
Materi : Pertidaksamaan KuadratPembahasan :
2x² + 6x + 1 > 2x + 7
2x² + 6x + 1 - 2x - 7 > 0
2x² + 4x - 6 > 0
x² + 2x - 3 > 0
(x + 3)(x - 1) > 0
Hp : {x < -3 atau x > 1}
2x^2 + 6x - 2x + 1 - 7 = 0
2x^2 + 4x - 6 = 0
x^2 + 2x - 3 = 0
(x - 1)(x + 3)
x > 1 atau x < -3