Jawaban:
[tex]\begin{aligned}\sf {3}^{2x - 3} &= \sf 27 \\ \sf {3}^{2x - 3}&= \sf {3}^{3} \\ \sf \cancel{3} {}^{2x - 3} &= \sf \cancel{3} {}^{3} \\ \sf 2x - 3&= \sf 3 \\ \sf 2x&= \sf 3 + 3 \\ \sf 2x&= \sf 6 \\ \sf x&= \sf \frac{6}{2} \\ \sf x&= \sf \red{3} \end{aligned}[/tex]
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Jawaban:
Penyelesaian :
[tex]\begin{aligned}\sf {3}^{2x - 3} &= \sf 27 \\ \sf {3}^{2x - 3}&= \sf {3}^{3} \\ \sf \cancel{3} {}^{2x - 3} &= \sf \cancel{3} {}^{3} \\ \sf 2x - 3&= \sf 3 \\ \sf 2x&= \sf 3 + 3 \\ \sf 2x&= \sf 6 \\ \sf x&= \sf \frac{6}{2} \\ \sf x&= \sf \red{3} \end{aligned}[/tex]
'조슈아' (Svt)