SEGITIGA
DE = EC = x
segitiga DEC siku di E
Maka
DC = x√2
3 - x = x√2
x + x√2 = 3
x(1 + √2) = 3
x = 3/(1 + √2)
x = 3/(1 + √2) × (1 - √2)/(1 - √2)
x = 3(1 - √2) / (1 - 2)
x = 3√2 - 3
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SEGITIGA
DE = EC = x
segitiga DEC siku di E
Maka
DC = x√2
3 - x = x√2
x + x√2 = 3
x(1 + √2) = 3
x = 3/(1 + √2)
x = 3/(1 + √2) × (1 - √2)/(1 - √2)
x = 3(1 - √2) / (1 - 2)
x = 3√2 - 3
thanks!!