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2x - 4y = 0......(2)
3x + 2y = 8| x2| 6x + 4y = 16
2x - 4y = 0| x3|
y = 1
3x + 2y = 8
3x + 2(1) = 8
3x + 2 = 8
3x = 8 - 2
3x = 6
x = 6/3
x = 2
Jadi, X = 2 dan Y = 1
2x - 4y = 0 --> kedua ruas dibagi 2
------------
3x + 2y = 8
x - 2y = 0
------------ +
4x = 8
x = 2
substitusi x = 2 ke salah satu persamaan.
ambil persamaan 2x - 4y = 0
2(2) - 4y = 0
4y = 4
y = 1
jadi, x = 2 dan y = 1.