Question

Nilai stasioner fungsi g(x)= x³-3x²-24x-7 adalah...

Answer 1

Titik stasioner dapat ditemukan jika g'(x) = 0
⇔3x²-6x-24 = 0
⇔x²-2x-8 = 0
⇔(x+2)(x-4) = 0
⇔x = -2, 4

Jika x = -2, g(-2) = 21
Jika x = 4, g(4) = -87

∴ Titik stasionernya (-2,21) dan (4,-87)