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Verified answer
1.)x-1 < 2
x < 3
x-1 ≥ 0
x ≥ 1
Irisan : 1 ≤ x < 3
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2.)
-x+1 < 2
-x < 1
x > -1
x-1 < 0
x < 1
Irisan : -1 < x < 1
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Gabungan dari kedua irisan :
-1 < x < 3
Jadi nilai x yang memenuhi pertidaksamaan :
E