Question

Nilai minimum fungsi f(x,y) = 3x+4y, yang memenuhi sistem pertidaksamaan x+y ≥ 8, x+3y ≥ 12, x ≥ 0, y ≥ 0 adalah ...

Answer 1

X+y = 8 
x=0, y =8
y =0, x = 8

x+3y =12
x = 0, y= 4
y=0 , x = 12

x+y = 8
x+3y = 12
..............(-)
-2y = - 4
y = 2 , x= 8-2= 6

titik pojok daerah HP x+y≥ 8, x + 3y ≥ 12. x ≥ 0, y≥ 0
(0,8) = 8 (4) = 32
(12,0)= 12(3)= 36
(6,2) =6(3)+2(4) = 18+8 = 26

nilai minimum = 26
.