Jawaban:
nilai minimum f(x) = 3x² + 6x - 24 adalah -27
Penjelasan dengan langkah-langkah:
f(x) = 3x² + 6x - 24
a = 3, b = 6, c = -24
nilai maksimum:
= [tex] - \dfrac{b}{2a} [/tex]
[tex] = - \dfrac{6}{2(3)} [/tex]
[tex] = - \dfrac{6}{6} [/tex]
[tex] = - 1[/tex]
Nilai minimum:
3x² + 6x - 24
= 3(-1)² + 6(-1) - 24
= 3 - 6 - 24
= -3 - 24
= -27
nilai minimum fungsi f(x) = 3x² + 6x -24
adalah - 27
Penjelasan:
fungsi f(x) diturunkan dan di sama dengan kan 0
f'(x) = 6x + 6 = 0
6x = -6
x = -6/6
x = -1
substitusi -1 ke persamaan f(x)=3x² + 6x -24
f(x) = 3x² + 6x -24
f(-1) = 3(-1)² + 6(-1) - 24
= 3 + (-6) - 24
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Jawaban:
nilai minimum f(x) = 3x² + 6x - 24 adalah -27
Penjelasan dengan langkah-langkah:
f(x) = 3x² + 6x - 24
a = 3, b = 6, c = -24
nilai maksimum:
= [tex] - \dfrac{b}{2a} [/tex]
[tex] = - \dfrac{6}{2(3)} [/tex]
[tex] = - \dfrac{6}{6} [/tex]
[tex] = - 1[/tex]
Nilai minimum:
3x² + 6x - 24
= 3(-1)² + 6(-1) - 24
= 3 - 6 - 24
= -3 - 24
= -27
Jawaban:
nilai minimum fungsi f(x) = 3x² + 6x -24
adalah - 27
Penjelasan:
fungsi f(x) diturunkan dan di sama dengan kan 0
f(x) = 3x² + 6x - 24
f'(x) = 6x + 6 = 0
6x = -6
x = -6/6
x = -1
substitusi -1 ke persamaan f(x)=3x² + 6x -24
f(x) = 3x² + 6x -24
f(-1) = 3(-1)² + 6(-1) - 24
= 3 + (-6) - 24
= -27