Question

Nilai minimum dari f(x)= x²+4x-12

Answer 1

F(x) = x² + 4x -12
nilai min = D/-4a = (b² - 4ac) /(-4 a)
=(16 +48)/(-4)
= -16
..
atau
f'(x) =0
2x + 4 = 0
x= -2
f(-2) = 4 - 8 - 12 = -16