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Tentukan turunan fungsinya:
f'(x) = 12 - 3x²
Akan stasioner apabila f'(x) = 0
0 = 12 - 3x²
0 = 3(4 - x²)
0 = 4-x²
0 = (2+x)(2-x)
Didapat absis minimum/maksimum di x = -2 atau x = 2
Substitusi pada f(x):
f(-2) = 12(-2) - (-2)³ = -24 + 8 = -16 [Minimum]
f(2) = 12(2) - 2³ = 24 - 8 = 16
Menyebabkan nilai minimum lokal dari fungsi adalah -16