Question

Nilai maksimum fungsi f(x)=3(x+4)^2-6 adalah

Answer 1

F(x) = 3(x + 4)² - 6
f(x) = 3(x² + 8x + 16) - 6
f(x) = 3x² + 24x + 48 - 6
f(x) = 3x² + 24x + 42

f'(x) = 6x + 24

f'(x) = 0
6x + 24 = 0
6x = -24
x = -4

nilai maksimum
3(-4 + 4)² - 6
= 3(0)² - 6
= -6