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syarat numerik : a > 0
m + 1 > 0
m > - 1
syarat khusus
D < 0
b² - 4.a.c < 0
(- 2m)² - 4.(m + 1).(m - 3) < 0
4m² - 4(m² - 2m - 3) < 0
4m² - 4m² + 8m + 12 < 0
8m < - 12
m <
m <
jadi nilai x = {x/ > x > - 1 ; x ∈ R }
= mx² + x² - 2m²x + 6mx
aku bisanya cuman sampe ini