Question

Nilai dari ²log32 + ³log27 - ⁴log16 = BANTUIN PAKE CARA

Answer 1

²log32+³log27-⁴log16=
²log2^5+³log3³-⁴log4²
5.²log2+3.³log3-2.⁴log4
5.1+3.1-2.1= 5+3-2 =6

Answer 2

²log32 = x
2^x = 32
x = 5

³log27 = x
3^x = 27
x = ∛27 =  3

4log16 = x
4^x = 16
x = 2

Mka hasilnya = 5+3-2 = 6

Maaf y kl salah

Good Luck! :D