Question

Nilai dari integral (4cos^2X - 2) dx adalah....

Answer 1

∫(4cos^2x - 2) dx = ∫2(2cos^2x - 1) dx
= 2∫(2cos^2x - 1) dx
= 2∫(2cos^2x - (cos^2x + sin^2x)) dx
= 2∫(cos^2x - sin^2x) dx
= 2∫cos(2x) dx
= 2∫cos(2x) d(2x)/2
= ∫cos(2x) d(2x)
= sin(2x) + C

Answer 2

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