Question

Nilai dari imtegral tolong bantu

Answer 1

Integral (1-3) [3x^2 + 4x -3] dx

= x^3 + 2x^2 -3x +C] (1-3)

= [(3)^3 + 2(3)^2 - 3(3) +C] - [1^3 + 2(1)^2 - 3(1) +C]

= 27 +18 -9 - 1 - 2 + 3

= 36