Nilai dari (√6-√3)^2 ÷ 3-2√3=.... Question from @ywld36

October 2018 2 358 Report

Nilai dari (√6-√3)^2 ÷ 3-2√3=

ImmanuelSinaga (√6 - √3)² = [√3 (√2 - 1) ]²
3 - 2√2 = (1 - √2)²

[√3 (√2 - 1) ]² = [-√3 (1 - √2 ) ]² = (-√3)² = 3
(1 - √2)² (1 - √2)²

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devanaquarius $\bold{(\sqrt{6}-\sqrt{3})^2 : 3 - 2\sqrt{3} = (\sqrt{6} - \sqrt{3})^2}\\\\
\bold{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=[\sqrt{3} (\sqrt{2} - 1]^2}\\\\
\bold{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~= 3 - 2\sqrt{2}}\\\\
\bold{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(1 - \sqrt{2})^2}\\\\
\bold{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(-\sqrt{3})^2}\\\\
\bold{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\boxed{\bold{3}}}}$

"semoga membantu"

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