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Verified answer
²log 125 × ³log 4 × ⁵log 3= ²log 5³ × ³log 2² × ⁵log 3
= (3 × 2) × ²log 5 × ⁵log 3 × ³log 2
= 6 × ²log 2
= 6
Verified answer
²log 125 × ³log 4 × 5log 3= ²log 5³ × ³log 2² × 5log 3
= 3 ²log 5 × 2 ³log 2 × 5log 3
= 6 × ²log 5 × 5log 3 × ³log 2
= 6 × ²log 3 × ³log 2
= 6 × ²log 2
= 6 × 1
= 6