To find the value of x + ½ from the expression -2(1-2x)(x-1)-(2x-1), we can simplify the expression first by using the distributive property and then combining like terms.
Starting with the expression:
-2(1-2x)(x-1)-(2x-1)
First, we can expand the expression inside the parentheses using the distributive property:
-2(1-2x)(x-1) = -2(x(x-1)-2x(1-1)) = -2(x^2-x)
Then, we can substitute this expression back into the original expression:
-2(x^2-x)-(2x-1)
Next, we can distribute the negative sign to both terms inside the parentheses:
-2x^2 + 2x - 2x + 1
Simplifying further by combining like terms, we get:
-2x^2 + 1
Now, we can set this expression equal to x + ½ and solve for x:
-2x^2 + 1 = x + ½
Rearranging this equation, we get a quadratic equation in standard form:
2x^2 - x - 1/2 = 0
We can solve for x using the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac))/(2a)
where a = 2, b = -1, and c = -1/2.
Plugging in these values, we get:
x = (-(-1) ± sqrt((-1)^2 - 4(2)(-1/2)))/(2(2))
x = (1 ± sqrt(5))/4
Therefore, the value of x + ½ is:
x + ½ = (1 ± sqrt(5))/4 + 1/2
x + ½ = (1 ± sqrt(5))/4 + 2/4
x + ½ = (1 ± sqrt(5) + 2)/4
x + ½ = (3 ± sqrt(5))/4
So, the two possible values of x + ½ are (3 + sqrt(5))/4 and (3 - sqrt(5))/4.
To find the value of x + ½ from the expression -2(1-2x)(x-1)-(2x-1), we can simplify the expression first by using the distributive property and then combining like terms.
Starting with the expression:
-2(1-2x)(x-1)-(2x-1)
First, we can expand the expression inside the parentheses using the distributive property:
-2(1-2x)(x-1) = -2(x(x-1)-2x(1-1)) = -2(x^2-x)
Then, we can substitute this expression back into the original expression:
-2(x^2-x)-(2x-1)
Next, we can distribute the negative sign to both terms inside the parentheses:
-2x^2 + 2x - 2x + 1
Simplifying further by combining like terms, we get:
-2x^2 + 1
Now, we can set this expression equal to x + ½ and solve for x:
-2x^2 + 1 = x + ½
Rearranging this equation, we get a quadratic equation in standard form:
2x^2 - x - 1/2 = 0
We can solve for x using the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac))/(2a)
where a = 2, b = -1, and c = -1/2.
Plugging in these values, we get:
x = (-(-1) ± sqrt((-1)^2 - 4(2)(-1/2)))/(2(2))
x = (1 ± sqrt(5))/4
Therefore, the value of x + ½ is:
x + ½ = (1 ± sqrt(5))/4 + 1/2
x + ½ = (1 ± sqrt(5))/4 + 2/4
x + ½ = (1 ± sqrt(5) + 2)/4
x + ½ = (3 ± sqrt(5))/4
So, the two possible values of x + ½ are (3 + sqrt(5))/4 and (3 - sqrt(5))/4.