Question

nilai dari ∫01​(4x2+5x)dx adalah
tolong with cara
​

Answer 1

[tex] = \int _{0}^{1} (4 {x}^{2} + 5x)dx[/tex]

[tex] = [ \frac{ {4x}^{2 + 1} }{2 + 1} + \frac{ {5x}^{1 + 1} }{1 + 1} ]_{0}^{1} [/tex]

[tex] = [ \frac{ {4x}^{3} }{3} + \frac{ {5x}^{2} }{2} ]_{0}^{1} [/tex]

[tex] = ( \frac{4(1) {}^{3} }{3} + \frac{5(1) {}^{2} }{2} ) - ( \frac{4(0) {}^{3} }{3} + \frac{5(0) {}^{2} }{2} )[/tex]

[tex] = ( \frac{4}{3} + \frac{5}{2} ) - (0 + 0)[/tex]

[tex] = ( \frac{8 + 15}{6} ) + (0)[/tex]

[tex] = \frac{23}{6} [/tex]