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Verified answer
L(OH)2 -> L^2+ + 2OH^-Mol L(OH)2 = 1/2 x 0,04 = 0,02 mol
Mr L(OH)2 = massa/mol
= 3,16/0,02 = 158
Mr L(OH)2 = Ar L + 2Ar O + 2Ar H
158 = Ar L + 32 + 2
Ar L = 124 gr/mol