Respuesta:
holis ......................
[tex]\int\limits^a_b {x} \, dx[/tex]
Explicación:
[tex]\sqrt[n]{x} \pi x^{2} \sqrt[n]{x} \beta \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n[/tex]
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Verified answer
Respuesta:
holis ......................
Respuesta:
[tex]\int\limits^a_b {x} \, dx[/tex]
Explicación:
[tex]\sqrt[n]{x} \pi x^{2} \sqrt[n]{x} \beta \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n[/tex]