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f'(x) = -------------------------------
(x²-x+2)²
-2x²-4x+6
f'(x) = ------------------------
(x²-x+2)²
f'(x) = 0 ⇒ tangente horizontal
-2x²-4x+6=0
Las raíces son x₁ = -3 y x₂ = 1
Luego: f(-3) = -2/7
f(1) = 2