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Z - liczba atomowa
srebro- Ag- 47
A1= Z+n= 47+60 = 107 - pierwsza liczba masowa
A2= ?
X1=51,8%
X2=100%-51,8%=48,2%
masa at.= A1·X1% + A2·X2% : 100%
107,9= 107· 51,8% + 48,2· A2 : 100%
10790= 5542,6+48,2·A2
48,2·A2= 5247,4
A2=108,9≈ 109 - druga liczba masowa