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NaOH + HCN ===> NaCN + H₂O
Mula 0,25 mmol 0,25 mmol
Reaksi -0,25 mmol -0,25 mmol +0,25 mmol +0,25 mmol
Sisa - - 0,25 mmol 0,25 mmol
NaCN ternyata terdapat 0,25 mmol, maka Konsentrasinya
[NaCN] = n/Vtotal = 0,25 mmol / 100 ml = 2,5 x 10⁻³
Ph NaCN :
[H⁺] =
[H⁺] =
[H⁺] =
[H⁺] = 10⁻⁴√5
Ph = -log [H⁺]
Ph = -log (10⁻⁴√5)
Ph = 4-log√5
Ph = 4-log2,2 (B)
Semoga Membantu!!1
Terbaiknya!!!