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CH₄ + 2 O₂ ---> CO₂ + 2 H₂O
Spalanie całkowite propenu:
2 C₃H₆ + 9 O₂ ---> 6 CO₂ + 6 H₂O
2C3H6---9O2=6CO2+6H2O
METANU: CH4+2O2=----CO2+2H2O