napisz równanie reakcji całkowitego spalania-- etanu i butenu.
2C2H6+7O2----->4CO2+6H2O całkowite
2C2H6+5O2----->4CO+6H2O
2C2H6+3O2----->4C+6H2O
C4H8+6O2----->4CO2+4H2O całkowite
C4H8+4O2----->4CO+4H2O
C4H8+2O2----->4C+4H2O
2 CH₃ - CH₃ + 7 O₂ ---> 4 CO₂ + 6 H₂O
CH₃ - CH₂ - CH = CH₂ + 6 O₂ ---> 4 CO₂ + 4 H₂O
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2C2H6+7O2----->4CO2+6H2O całkowite
2C2H6+5O2----->4CO+6H2O
2C2H6+3O2----->4C+6H2O
C4H8+6O2----->4CO2+4H2O całkowite
C4H8+4O2----->4CO+4H2O
C4H8+2O2----->4C+4H2O
2 CH₃ - CH₃ + 7 O₂ ---> 4 CO₂ + 6 H₂O
CH₃ - CH₂ - CH = CH₂ + 6 O₂ ---> 4 CO₂ + 4 H₂O