Napisz równania reakcji spalania niecałkowitego etanolu
C₂H₆O + 2O₂ --> 2CO + 3H₂O
C₂H₆O + O₂ --> 2C + 3H₂O
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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C₂H₆O + 2O₂ --> 2CO + 3H₂O
C₂H₆O + O₂ --> 2C + 3H₂O
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)