Napisz równania reakcji spalania calkowitego estrów:
a) octan propylu
b) mrówczanu etylu
c) maślanu metylu.
a) 2CH₃COOC₃H₇ + 13O₂ ---> 10CO₂ + 10H₂O
b) 2HCOOC₂H₅ + 7O₂ ---> 6CO₂ + 6H₂O
c) 2C₃H₇COOCH₃ + 13O₂ ---> 10CO₂ + 10H₂O
a) CH3COOC2H5 + 5 02 -> 4 CO2 + 4 H20
b)CH3COOC2H5+3O2 -->4 H2O+2CO2
c)C3H7COOH+CH3OH---->C3H7COOCH3+H2o
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a) 2CH₃COOC₃H₇ + 13O₂ ---> 10CO₂ + 10H₂O
b) 2HCOOC₂H₅ + 7O₂ ---> 6CO₂ + 6H₂O
c) 2C₃H₇COOCH₃ + 13O₂ ---> 10CO₂ + 10H₂O
a) CH3COOC2H5 + 5 02 -> 4 CO2 + 4 H20
b)CH3COOC2H5+3O2 -->4 H2O+2CO2
c)C3H7COOH+CH3OH---->C3H7COOCH3+H2o
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