Napisz równania reakcji spalania.
a) etanu
b) propanu
c) heptanu
a) etanu
b) propanu
c) heptanu
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2C2H6 + 7 O2---->4CO2 + 6H2O
2C2H6 + 5 O2---->4CO + 6H2O
2C2H6 + 3 O2---->4C + 6H2O
b)
C3H8 + 5 O2 --> 3 CO2 +4 H20
2 C3H8 + 7 O2 --> 6 CO + 8 H20
C3H8 + 2 O2 --> 3 C + 4 H20
c)
C7H16+11O2--> 7CO2+8H2O
C7H16+15/2 O2--> 7CO +8 H2O/*2
2C7H16+15O2-->14CO + 16H2O
C7H16+4O2-->7C + 8H2O