Napisz równania reakcji otrzymywania podanych soli 3 metodami. a) chlorek żelaza (III) b) azotan(V) potasu c) fosforan(V) sodu
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chlorek żelaza(III)- FeCl3(sól beztlenowa)
1.6HCl+2Fe=2FeCl3+3H2
2.2Fe+3Cl2=2FeCl3
3.6HCl+Fe2O3=2FeCl3+3H2O
4.3HCl+Fe(OH)3=FeCl3+3H2O
fosforan(V)sodu-Na3PO4
1.2H3PO4+6Na=2Na3PO4+3H2
2.2H3PO4+3Na2O=2Na3PO4+3H2O
3.H3PO4+3NaOH=Na3PO4+3H2O
4.12NaOH+P4O10=4Na3PO4+6H2O
5.P4O10+6Na2O=4Na3PO4
azotan (V) potasu
N2O5 + K2O---->2KNO3
2HNO3 + K2O---->2KNO3 + H2O
HNO3 + KOH---->KNO3 + H2O
2HNO3 + 2K---->2KNO3 + H2
a)2Fe+3Cl2--->2FeCl3
Fe(OH)3+3HCl--->FeCl3+3H2O
Fe2O3+6HCl--->2FeCl3+3H2O
b)KOH+HNO3--->KNO3+H2O
K2O+2HNO3--->2KNO3+H2O
N2O5+K2O--->2KNO3
c)3NaOH+H3PO4--->Na3PO4+3H2O
6Na2O+P4O10--->4Na3PO4
3Na2O+2H3PO4--->2Na3PO4+3H2O