Napisz równania reakcji CaCl2 i MgCl2 z mydłem - steraynianem sodu.
prosze o pomoc !! ;)
2C₁₇H₃₅COONa + CaCl₂ --> (C₁₇H₃₅COO)₂Ca + 2NaCl
2C₁₇H₃₅COONa + MgCl₂ --> (C₁₇H₃₅COO)₂Mg + 2NaCl
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
CaCl2+2C17H35COONa--->(C17H35COO)2Ca+2NaCl
MgCl2+2C17H35COONa--->(C17H35COO)2Mg+2NaCl
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2C₁₇H₃₅COONa + CaCl₂ --> (C₁₇H₃₅COO)₂Ca + 2NaCl
2C₁₇H₃₅COONa + MgCl₂ --> (C₁₇H₃₅COO)₂Mg + 2NaCl
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
CaCl2+2C17H35COONa--->(C17H35COO)2Ca+2NaCl
MgCl2+2C17H35COONa--->(C17H35COO)2Mg+2NaCl