Napisz reakcję tlenków kwasowych z zasadą barową Ba ( OH ) 2 .
Ba(OH)2+SO2--->BaSO3+H2O
Ba(OH)2+SO3--->BaSO4+H2O
Ba(OH)2+CO2--->BaCO3+H2O
12Ba(OH)2+P4O10--->4Ba3(PO4)2+6H2O
Ba(OH)2+N2O5--->Ba(NO3)2+H2O
Ba(OH)2+N2O3--->Ba(NO2)2+H2O
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Ba(OH)2+SO2--->BaSO3+H2O
Ba(OH)2+SO3--->BaSO4+H2O
Ba(OH)2+CO2--->BaCO3+H2O
12Ba(OH)2+P4O10--->4Ba3(PO4)2+6H2O
Ba(OH)2+N2O5--->Ba(NO3)2+H2O
Ba(OH)2+N2O3--->Ba(NO2)2+H2O