Propyn ma wzór C3H4, a nie C3H2
1. PROPYN:
C3H4+4O2--->3CO2+2H2O
2C3H4+5O2--->6CO+4H2O
C3H4+O2--->3C+2H2O
BUTYN
2C4H6+11O2--->8CO2+6H2O
2C4H6+7O2--->8CO+6H2O
2C4H6+3O2--->8C+6H2O
2. mC3H4=3*12u+4*1u=40u
Stosunek masowy:
mC:mH=36:4=9:1
36u---x%
40u---100%
x=90%C
100%-90%=10%H
mC4H6=4*12u+6*1u=54u
mC:mH=48:6=8:1
48u---x%
54u---100%
x=88,89%C
100%-88,89%=11,11%H
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Propyn ma wzór C3H4, a nie C3H2
1. PROPYN:
C3H4+4O2--->3CO2+2H2O
2C3H4+5O2--->6CO+4H2O
C3H4+O2--->3C+2H2O
BUTYN
2C4H6+11O2--->8CO2+6H2O
2C4H6+7O2--->8CO+6H2O
2C4H6+3O2--->8C+6H2O
2. mC3H4=3*12u+4*1u=40u
Stosunek masowy:
mC:mH=36:4=9:1
36u---x%
40u---100%
x=90%C
100%-90%=10%H
mC4H6=4*12u+6*1u=54u
Stosunek masowy:
mC:mH=48:6=8:1
48u---x%
54u---100%
x=88,89%C
100%-88,89%=11,11%H