Odpowiedź:
penten + fluor
a) CH3-CH=CH-CH2-CH3 + F2 -> CH3-CH(F) - CH(F) -CH2-CH3
b) C5H10 + F2 -> C5H10F2
buten + wodór
a) CH3-CH2-CH=CH2 + H2 -> CH3-CH2-CH2-CH3
b) C4H8 + H2 -> C4H10
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Odpowiedź:
penten + fluor
a) CH3-CH=CH-CH2-CH3 + F2 -> CH3-CH(F) - CH(F) -CH2-CH3
b) C5H10 + F2 -> C5H10F2
buten + wodór
a) CH3-CH2-CH=CH2 + H2 -> CH3-CH2-CH2-CH3
b) C4H8 + H2 -> C4H10